Question

1). A train is moving with a velocity of 10m/s. It attains an acceleration of 4m/s after 5 seconds. Find the distance covered by the train at that time ?

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Answer 1

Given :

• A train is moving with a velocity of 10m/s.
• It attains an acceleration of 4m/s after 5 seconds.

To Find :

• Find the distance covered by the train at that time ?

Solution :

• First equation of motion :

➣ v = u + at

Where,

• v = Final Velocity
• u = Initial Velocity = 10m/s
• a = Acceleration = 4m/s²
• t = Time = 5 seconds

Finding the final velocity :

➣ v = 10 + (4 × 5)

➣ v = 10 + 30

➣ v = 30

• Final Velocity = 30m/s

Second equation of motion :

• s = ut + (at²)/2

Where,

• s = Displacement
• v = Final Velocity = 30m/s
• u = Initial Velocity = 10m/s
• a = Acceleration = 4m/s²
• t =Time = 5 seconds

Finding the distance covered by the train :

➣ s = (10 × 5) + (4 × 5²)/2

➣ s = 50 + (2 × 25)

➣ s = 50 + 50

➣ s = 100

Hence,

• The distance covered by the train at that time is 100m.

Answer 2

Answer:

The distance covered by the train is 100 m .