1. A train travelling with a speed of 25 m/s breaks are applied so that to produce a acceleration of -0.05m/s sq. find the velocity before it comes to rest ?
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Hello !
u = 25 m/s
v = 0 m/s
a = - 0.05 m/s²
v = u + at
0 = 25 - 0.05 x t
t = 500 seconds
after coming to rest
s = ut + 1/2 at ²
s = 25 x 500 - 1/2 x 0.05 x 500 x 500
s = 12500 - 6250
s = 6250 m
u = 25 m/s
v = 0 m/s
a = - 0.05 m/s²
v = u + at
0 = 25 - 0.05 x t
t = 500 seconds
after coming to rest
s = ut + 1/2 at ²
s = 25 x 500 - 1/2 x 0.05 x 500 x 500
s = 12500 - 6250
s = 6250 m
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