1. A tree breaks due to storm and the broken part bends so that the top of the tree touches the ground making an angle of 30 with the ground. The distance between the foot of the tree to the point where the top touches the ground is 8m. Find the height of the tree.
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Answered by
5
Answer:
Answer
Let the Height of the Tree =AB+AD
and given that BD=8 m
Now, when it breaks a part of it will remain perpendicular to the ground (AB) and remaining part (AD) will make an angle of 30o
Now, in △ABD
cos30o=ADBD⇒BD=23AD⇒AD=32×8
also, in the same Triangle
tan30o=BDAB⇒AB=38
∴ Height of tree =AB+AD=(316+38)m=324m=83m
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Answered by
5
Answer:
Let the Height of the Tree =AB+AD
and given that BD=8 m
Now, when it breaks a part of it will remain perpendicular to the ground (AB) and remaining part (AD) will make an angle of 30
o
Now, in △ABD
cos30
o
=
AD
BD
⇒BD=
2
3
AD
⇒AD=
3
2×8
also, in the same Triangle
tan30
o
=
BD
AB
⇒AB=
3
8
∴ Height of tree =AB+AD=(
3
16
+
3
8
)m=
3
24
m=8
3
m
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