1. A tree is broken at a height of 6 m from the ground and its top touches the ground
at a distance of 8 m from the base of tree. Find the original height of the tree.
Answers
Answered by
0
By Pythagorean’s theorem
H^2= b^2 + p^2
Highly of tree = 64 + 36
Underroot 100
10
So original highly of tree = 10 + 8
= 18
H^2= b^2 + p^2
Highly of tree = 64 + 36
Underroot 100
10
So original highly of tree = 10 + 8
= 18
Answered by
4
x² = 6² + 8²
x = √(36 + 64)
x = √(100) = 10m
Original height
= x + 6m
= 16m
Attachments:
Similar questions