1) A truck driver, once in a week, leaves his house and drives to the river dock to pick up supplies. At 6:05
PM, one-fifth of the way to the dock, he passes the Temple. At 6:15 PM, one-third of the way, he passes
the Amritsari Dhaba. At what time does he reach the dock?
Answers
Given : At 6:05 PM, one-fifth of the way to the dock, he passes the Temple.
At 6:15 PM, one-third of the way, he passes the Amritsari Dhaba.
To Find : At what time does he reach the dock
Solution:
Total Distance = 15d
. At 6:05 PM, one-fifth of the way to the dock = (1/5) 15d = 3d
At 6:15 PM, one-third of the way = (1/3) 15d = 5d
Time from 6:05 PM to 6:15 PM = 10 Mins
Hence 5d - 3d = 2d distance covered in 10 min
Distance remained to covered after 6 : 15PM
= 15d - 5d = 10d
2d distance covered in 10 min
=> d distance covered in 5 min
=> 10d distance covered in 50 min
he reach the dock = 6:15 + 50 Mins
= 7 :05 PM
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