Physics, asked by sahba55, 9 months ago

1. A truck starts from rest and accelerates at 3 m/s^2
for 5 s and then continues with constant velocity.
Calculate the distance covered in 15 s since it starts
from rest.
[Ans : 187.5 m]

Answers

Answered by JunaidMirza
8

Answer:

187.5 m

Explanation:

Distance covered in first 5 s

S = ut + 0.5at²

= (0 × 5) + (0.5 × 3 × 5²)

= 75/2 m

= 37.5 m

Velocity at the end of 5 s

v = u + at

= 0 m/s + (3 m/s² × 5 s)

= 15 m/s

From now, truck is moving with a uniform velocity of 15 m/s

Distance covered in rest of the 10 s

D = Speed × Time

= 15 m/s × 10 s

= 150 m

Total distance covered = 37.5 m + 150 m

= 187.5 m

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