Question

1. A) Two bulbs A and B of equal capacity contains 1o gm of oxygen and Oxone respectively which bulb will have

Answer 1

Answer:YOUR QUESTION SHOULD BE-

Two bulbs A and B of equal capacity contains 10 gram dioxygen and Ozone respectively.Which bulb will have greater number of atoms and which will have greater number of molecules.

Explanation:NOW ANSWER-

According to Mole theory 32 g Oxygen = 6.022 ×1023 molecules of oxygen

                                                        = 2 × 6.022 ×1023 = 12.044 atoms of oxygen

So for Bulb A having 10 g oxygen

No of molecules of oxygen = 6.022 ×1023  × 10⁄32= 1.88×1023  

No of atoms in this sample = 2 × 1.88×1023  = 3.76 ×1023

Similarly for Bulb B having 10 g ozone

No of molecules of ozone = 6.022 ×1023  × 10⁄48= 1.254 ×1023  

No of atoms in this sample = 3 × 1.254×1023  = 3.76 ×1023

Thus, Bulb A has more number of molecules incomparision to Bulb B, while both the Bulbs has same number of oxygen atoms.

HOPE THIS HELPS!!!!