1. A vertical pole 5 m long cast a shadow 2m long on the ground at the same time. a tower casts a shadow 25m long ,find the height of the tower .
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Step-by-step explanation:
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Step-by-step explanation:
Height of pole=AB= 5 m
Length of shadow of pole =BC=2 m
Length of shadow of tower=EF=25 m
In △ABC and △DEF
∠B=∠E=90
∘
both 90
∘
as both are vertical to ground
∠C=∠F (same elevation in both the cases as both shadows are cast at the same time)
∴△ABC∼△DEF by AA similarity criterion
We know that if two triangles are similar, ratio of their sides are in proportion
So,
DE
AB
=
EF
BC
⇒
DE
6
=
25
4
⇒DE=6×7=42 m
Hence the height of the tower is 42 m
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