1.A water pump raises 50 litre of water through a height of 25m in 5s .Calculate the power of pump required.
(Take g=10 N kg and density of water =1000 kg m cube)
Answers
Answered by
5
given
h=25m
t=5sec
v=50lits
word done= mgh=vdgh
power =wd/t= 50*1000*10*25/5=2500000watts
h=25m
t=5sec
v=50lits
word done= mgh=vdgh
power =wd/t= 50*1000*10*25/5=2500000watts
sivankavinpuram:
Vdgh
But the answer is 2500 W
mass=volume*density
Vdgh?
sorry consider d as 1 cuz density of water in SI units is 1
Thanks
volume*density *gravity*height
But vgdh means
Thanks
Ok
Answered by
2
Answer:
Explanation:mass=volume*density
=(50litres)(1000kg/m^3)
=(50/1000m^3)(1000kg/m^3)
=50kg
use, energy=mgh=50kg (10N/kg)(25m)
=12500Nm=12500j
power=energy/time
= 12500j/5sec
=2500j/sec
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