Question

1. A winding drum raises a cage through a height of 120 m. The cage has, at first, an acceleration of 1.5 m/s2 until the velocity of 9 m/s is reached, after which the velocity is constant until the cage nears the top, when the final retardation is 6 m/s. Find the time taken for the cage to reach the top. ​

Answer 1

Explanation:

In acceleration from 0 to 9m/s

v=u+at

9 = 0 + 1.5t

1.5t = 9

9

-=68 1.5

s = ut + 1/2 * a * t ^ 2 s=0+ 1.5x6x6 2 ==27m