Question

1) A wire of resistance 20ohm is bent in the form
of closed circle what is the effective resistane
two
between points at the end of any diam-
eter of circle​

Answer 1

firstly it is clear that both halves of the circular wire will have 10 ohm resistance as lenght is halved.Now if u connect a battery across the diameter current will flow separately throu the upper and lower half just as if it is a parallel connection. so the net resistance will be 10*10/10+10=5ohm

Answer 2

Answer:

Explanation:two 10 (Ω) resistors are in parallel

Therefore 1/Rp = 1/10+1/10=2/10

Therefore Rp = 5 (Ω)