1
A woman is now 30 years olden than his
son. 15 years ago she was twice as
old as her son Find the both
pressent ageswoman is not 30 years older than his son 15 years ago she was twice as old as his son find their present ages
Answers
Answer:
Step-by-step explanation:
Let the woman's Present age be X
Then son's present age will be ( X- 30)
15 years ago
Woman was ( X - 15)
Son was (X-30) - 15 = X-45
But
ACQ
W = 2 (S)........ (15 years ago situation)
(X-15) = 2 (X-45)
X-15 = 2X - 90
X - 2X = - 90 + 15
- X = - 75
Multiplying both sides by (-)
X = 75
So the present ages are
Woman = 75 years
Son = 75 - 30 = 45 years
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Answer:
Present age of woman = w = 75 years old
Present age of son = s = 45 years old
Let Present age of woman = w years old
Present age of son = s years old
woman is now 30 years older than her son
w = s + 30 .........(1)
15 years ago ..,
woman was = w - 15 years old
son was = s - 15 years old
Then
she was twice as old.
w - 15 = 2 ( s - 15 )
w - 15 = 2s - 30
w = 2s - 30 + 15
w = 2s - 15 ...........(2)
Put the value of w from (1) to (2)
s + 30 = 2s - 15
s - 2s = - 15 - 30
- s = - 45
s = 45
Put the value of s in (1)
w = s + 30 .........(1)
w = 45 + 30
w = 75
Present age of woman = w = 75 years old
Present age of son = s = 45 years old