Question

1) A woman is seven times as old as her son. After 5 years, she will be four times as old as her son. What are the present ages of the mother and son?​

Answer 1

Answer:

• Mother's present age = 35 years.
• Son's present age = 5 years.

Explanation:

Given,

A woman is seven times as old her son.

Let's say her son's present age $\boldsymbol x$ yrs.

∴ Women's present age = $\boldsymbol {7x}$ yrs.

Now,

After 5 years she'll be 4 times the age of her son.

5 years later,

• Mother's age = $\boldsymbol {7x + 5}$ yrs.
• Son's age = $\boldsymbol {x + 5}$ yrs.

According to the question,

$\implies \: 7x + 5 = 4 \times (x + 5)$

Solving for $\boldsymbol x$

$\implies \: 7x + 5 = 4x + 20$

$\implies \: 7x - 4x= 20 - 5$

$\implies \: 3x= 15$

$\implies \: x= \dfrac{15}{3}$

$\therefore \boldsymbol{ x= 5}$

Hence,

• Son's present age = $\boldsymbol x$ = 5 years.
• Mother's present age = $\boldsymbol {7x}$ = 35 years.

__________________________

Answer 2

Answer:

son = 5 , mother =

Step-by-step explanation:35

let the present age of son be x

present age of women = 7x

after five years,

7x+5 = 4(x+5)

7x+5 = 4x+20

3x = 15

x = 5

present age of son = 5

present age of women = 35