Question

1/a²+1/b²+1/c²=2 then find the value of 3abc

Answer 1

Step-by-step explanation:

1/a²+1/b²+1/c²=2

=> {(b²c²) + (a²c²) + (a²b²)} / (a²b²c²) = 2

=> (b²c²) + (a²c²) + (a²b²) /2 = (a²b²c²)

then abc = √(b²c²) + (a²c²) + (a²b²) /2

Multiply 3 in both sides...

3 abc = 3/√2 √[(b²c²) + (a²c²) + (a²b²)]