Question

1. AABC and A DBC are two isosceles triangles on
the same base BC and vertices A and D are on the
same side of BC (see Fig. 7.39). IF AD is extended
to intersect BC at P, show that
(1) A ABD = AACD
(ii) A ABP=AACP
(iii) AP bisects 2 Aas well as 2 D.
(iv) AP is the perpendicular bisector of BC.


Fig. 7.39​

Answer 1

Answer:

1. AABC and A DBC are two isosceles triangles on the same base BC and vertices A and D are on the. More

Explanation: