Math, asked by Larelmsd, 5 months ago

1. AABC is isosceles in which AE IBC, AE = 6 cm , BC = 9 cm, the area of
AABC is
(b) 54 cm
(c) 22.5 cm?
(d) 45
(a) 27 cm?
cm?

Answers

Answered by shivamrajpoot5213

1

Answer:

a 27 cm

Step-by-step explanation:

ae is base is 6cm

and heights bc is 9 CM

so area of triangle= 1/2 ×base ×height

= 1/2×6×9=27cm

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