Math, asked by gopalkgp90221, 6 months ago

1. आकृती 2.5 मध्ये रेषा RP || रेषा MS व रेषा DK
ही त्यांची छेदिका आहे. ÐDHP = 85°
तर खालील कोनांची मापे काढा.
(i) ÐRHD (ii) ÐPHG
(iii) ÐHGS (iv) ÐMGK

Answers

Answered by amitnrw
7

Given : रेषा RP || रेषा MS व रेषा DK ही त्यांची छेदिका आहे.  m∠DHP = 85°

Line RP || Line MS  are intersected by  transversal DK  

To Find : कोनांची मापे

Measure of angles

(i) ∠RHD

(ii) ∠PHG

(iii) ∠HGS

(iv) ∠MGK

Solution:

∠RHD and  ∠DHP forms a linear pair

Hence m∠RHD + m∠DHP = 180°

=> m∠RHD +   85° = 180°

=> m∠RHD = 95°

∠PHG and  ∠DHP forms a linear pair

Hence m∠PHG + m∠DHP = 180°

=> m∠PHG +   85° = 180°

=> m∠PHG = 95°

∠HGS and  ∠DHP are corresponding angles

=> m∠HGS  = m∠DHP

=> m∠HGS  = 85°

∠MGK and ∠HGS are vertically opposite angles

=> m∠MGK  =  m∠HGS

=> m∠MGK  = 85°

Learn More:

7. If a transversal intersects two lines parallel lines then prove that ...

brainly.in/question/18440350

If two interior angles on the same side of a transversal intersecting ...

brainly.in/question/15906419

Attachments:
Similar questions