Math, asked by abhijeet79dawane, 3 months ago

1) आकृतीत, रेख PQ ही वर्तुळाला P या बिंदूत स्पर्श करतो.
रेख OP ही त्रिज्या आहे. OQP = 40°; तर OPQ व
POQ ची मापे काढा.​

Answers

Answered by amitnrw
2

Given : आकृतीत, रेख PQ ही वर्तुळाला P या बिंदूत स्पर्श करतो.

रेख OP ही त्रिज्या आहे. OQP = 40°;

the line PQ touches the circle at the point P.

Line OP is the radius. OQP = 40°  

To Find : Measure of angles OPQ and the POQ.

OPQ व POQ ची मापे काढा.​

Solution:

line PQ touches the circle at the point P.

and OP is radius

=> ∠OPQ = 90°

   ∠OQP = 40°   Given

∠OPQ +  ∠OQP + ∠POQ = 180°   ( Sum of angles of triangle )

=>  90° + 40° +   ∠POQ = 180°

=> ∠POQ = 50°

∠OPQ = 90°

∠POQ = 50°

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Answered by mahajanlalit2006
0

Answer:

आकृतीत, रेख PQ ही वर्तुळाला P या बिंदूत स्पर्श करतो.

रेख OP ही त्रिज्या आहे. OQP = 40°; तर OPQ व

POQ ची मापे काढा.

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