Question

1. ab+2bc3ca+4abc
2. a^3+b^3+c^3-3abc

Answer 1

Answer:

1. a=3,b=0,c=−2

ab+2bc+3ca+4abc

=3×0+2×0×(−2)+3(−2)(3)+4(3)(0)(−2)

=0+0−18+0

=−18