Question

1. AB and CD are parallel sides of trapezium ABCD. Diagonals AC and BD
intersect at O. prove that ar(ΔAOD) = ar(ΔBOC).














ANSWER =
We know that triangle between same base and lie between the same parallel are equal in area

ar(ACD)=ar(BDC)
ar(AOD)+ar(DOC)=ar(BOC)+ar(DOC)
ar(AOD)=ar(BOC)

HOPE THIS IS HELP FULL FOR ALL

THANK YOU ​

Answer 1

Step-by-step explanation:

ar(ACD)=ar(BDC)

ar(AOD)+ar(DOC)=ar(BOC)+ar(DOC)

ar(AOD)=ar(BOC)