Question

.(1) ABC ~ A PQR, in A ABC, AB = 5.4 cm, BC = 4.2 cm, AC = 6.0 cm.
AB: PQ = 3:2. Construct A ABC and A POR.​

Answer 1

Answer:

Step-by-step explanation:

$identity \: used \: = (x + a)(x + b) \\ = {x}^{2} + (a + b)x + ab \\ \\ ({4b})^{2} + (9 + 7)4b + 9 \times 7 \\ = {16b}^{2} + (16)4b + 63 \\ = {16b}^{2} + 64b + 63$

Answer 2

Answer:

Step-by-step explanation:

\begin{gathered}identity \: used \: = (x + a)(x + b) \\ = {x}^{2} + (a + b)x + ab \\ \\ ({4b})^{2} + (9 + 7)4b + 9 \times 7 \\ = {16b}^{2} + (16)4b + 63 \\ = {16b}^{2} + 64b + 63\end{gathered}

identityused=(x+a)(x+b)

=x

2

+(a+b)x+ab

(4b)

2

+(9+7)4b+9×7

=16b

2

+(16)4b+63

=16b

2

+64b+63