Question

1) ABC is an isosceles triangle with AB = AC and AD is one of

its altitudes.[Fig 7.34 in pg no. 148]

(i) State the three pairs of equal parts in ΔADB and ΔADC.

(ii) Is ΔADB ≅ ΔADC? Why or why not?

(iii) Is ∠B = ∠C? Why or why not?

(iv) Is BD = CD? Why or why not?​

Answer 1

Answer:

i. In ∆ADB and ∆ ADC

angle BDA= CDA ... 90 °

Side AB = AC .. given

side AD= AD....common side

ii. From i RHS cc

iii. corresponding angles..

iv . corresponding sides..