Question

1) Δ ABC ~ Δ PBQ , ΔABC मध्ये AB = 3 सेमी, angle B=90degree BC=4 सेमी व त्रिकोणाच्या संगत बाजूचे गुणोत्तर 7:4 असल्यास ΔPBQ काढा.​

Answer 1

Steps of construction:

(1) Draw a line segment XY.

(2) Locate B, C on XY such that BC=4cm

(3)Construct a line segment BD, sufficiently large, such that ∠B=90°

(4)With C as centre and radius 5cm draw an arc, cutting BD at A; join AC.

Then, ABC is the required triangle.