1. ABC right angled at B, in which AC = 10 cm, AB - 8
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Finding out BC
According to the Pythagoras theorem
H2=B2-P2
As ABC right angled at B
Therefore,
10^2=BC2-8^2. (AC2=BC2-AB2)
100=BC2-64
BC2=100-64
BC=root under36
BC= 6
Therefore BC is 6 cm
According to the Pythagoras theorem
H2=B2-P2
As ABC right angled at B
Therefore,
10^2=BC2-8^2. (AC2=BC2-AB2)
100=BC2-64
BC2=100-64
BC=root under36
BC= 6
Therefore BC is 6 cm
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