Question

1. ABCD is a cyclic quadrilateral. ZBAO = 20° and ZBCO = 15º. Find ZAOC and ZADC.​

Answer 1

Answer:

3y-5-7x+5=180

3y-7x=180----------1

4y+20-4x=180

4y-4x=160

dividing each term by 4

y-x=40

y=40+x-------------2

putting 1 in2

3(40+x)-7x=180

120+3x-7x=180

-4x=60

x= -15

y=40-15

=25

so,

A=4*25 +20

=120

B=3*25-5

=70

C=-4*-15

=60

D=-7*-15+5

=110

Step-by-step explanation:

I don't think you meant to say Z since there is no Z