Question

1) ABCD is a rhombus in which the altitude from D to side AB bisects AB. Then angle A and angle B respectively are:
(Plz explain)

Answer 1

After drawing the figure Let the altitude drawn be DE I.e E is the midpoint of AB .in ∆ADE ,let hypotenuse be 2x,therefore AE =AB/2=x, therefore the base of angle A is x, By Pythagoras theorem p²=h²-b² p=√3x sin angle DAE=p/h=√3/2 see the table,when sin theta= √3/2,theta is 60°, Angle A is therefore 60 and B is 180-60°=120