Question

1. ABCD is a square of side 24 cm. EF is parallel to
BC and AE = 15 cm. By how much does
(i) the perimeter of AEFD exceed the perimeter
of EBCF?
(ii) the area of AEFD exceed the area of EBCF?

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Answer 1

(i)

the perimeter of EBCF

AB= AE+EB

24 = 15+EB  

EB= 9cm

perimeter of EBCF =  2(9+24)

P=66

the perimeter of AEFD

=2(24+15) = 78

the perimeter AEFD exceed = 78-66 =12

(ii)

Area of rectangle EBCF= EB*BC

9*24 = 216 cm

Area of rectangle AEFD

15*24 = 360

the perimeter AEFD exceed = 360-216 = 144cmsq