Question

1. ABCD is a square which is 576 m in area. AE = 4 m.
O is the midpoint of AB. If a semicircle EFG with O as centre is cut off
to accommodate a circular pillar, then find the area of the carpet
required to cover the remaining area.
NOTE:-( answer is 3328÷7msquare)​

Answer 1

Answer:

Area of square= side²

side²=576

side=24 cm

diameter of the circle= 24- 8=>16

Radius=8cm

Area of semicircle=1/2×πr²

=>1/2×22/7×16

=>25.14 ( approx)

Area of the leftover carpet= 576-25.14

=>550.86 cm²

Answer 2

Answer:

Step-by-step explanation:

Area of square =576 m^2

Side of square = 24m =AD

AO=OD =24/2=12

From figure

AO=12m ,AE=4m

EO=AO-AE=12-4=8

Area of semicircle =pie×r^2/2

22/7×1/2×8×8 = 22×4×8/7

88×8/7=704/7

576/1-704/7

4032-704 /7

3328/7 sq m