Question

1)
ABCD is a trapezium
AB 7.BC-12, observe
the figure and find FC.
​

Answer 1

Step-by-step explanation:

This Question Bellow To Trigonometry

In This I Give Some Tips

Sin

Tan

Answer 2

The length of FC is 23.4 cm

Explanation:

Given that AB = 7 cm

The length of BC = 12 cm

We need to determine the length of FC.

The length of FC can be determined by adding the lengths FE, ED and DC

Length of ED:

Since, the sides AB are ED are opposite sides and by the property of trapezium, the two sides AB and ED are equal.

Thus, AB = ED = 7 cm

Thus, the length of ED is 7 cm

Length of DC:

From the figure, it is obvious that BDC is a right angled triangle.

       $Sin \ 60^{\circ}=\frac{DC}{12}$

$Sin \ 60^{\circ} \times 12=DC$

       $10.4 \ cm=DC$

Thus, the length of DC is 10.4 cm

Length of FE:

First, we shall find the lengths of BD and AE

The length of BD is given by

$cos \ 60^{\circ}=\frac{12}{BD}$

     $BD=\frac{12}{cos \ 60^{\circ}}$

     $BD=6 \ cm$

Length of BD is 6 cm

Since, the BD and AE are heights of the trapezium, then BD and AE are equal.

Thus, BD = AE = 6 cm

Now, we shall find the length of FE

$tan \ 45^{\circ}=\frac{6}{FE}$

     $FE =\frac{6}{tan \ 45^{\circ}}$

     $FE= 6$

Thus, the length of FE is 6 cm

Thus, the length of FC is given by

FC = FE + ED + DC

     = 6 + 7 + 10.4

     = 23.4

Thus, the length of FC is 23.4 cm

Learn more:

(1) In the given figure abcd is a trapizium in which AB =7cM AD=BC=5cm ,DC=Xcm and distance between ab and dc is 4 cm find the valu of x and area of a trapezium ABCD

brainly.in/question/1055763

(2) In the given fig., ABCD is a trapezium with AB||CD and , ∠BCD = 60°, If BFEC is a sector of a circle with centre C and AB = BC = 7 cm and DE = 4 cm,then find the area of the shaded region.(Use π = 22/7, √3 =1.732).

brainly.in/question/2976094