Math, asked by jprabha230, 6 months ago

1)⎕ABCDis parallelogram.The ratio of∠A and∠B of this

parallelogram is5∶4.Find the measure of∠B,

→Theratio of∠Ato∠Bis⎕

Let the common multiple of the ratio be x.

Then∠A=5x°and∠B=⎕

∠A+∠B=180---→(interriorangles)

5x°+4x°=⎕

⎕=180

x=

180

9

x=⎕

∴∠B=4x

∠B=4×20°

∠B=⎕

∴The measure of∠B is80°​

Answers

Answered by rakeshchemist8
0

Answer:

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Answered by bindiyaj18
1

Answer:

80

Step-by-step explanation:

Let the common multiple of the given ratio then

∴∠A=5x

and∠B=4x

□ ABCD is a parallelogram.

∴∠A+∠B=180

[Adjacent angle of parallelogram are supplementary]

∴5x+4x=180

⇒9x=180

⇒x=180/9

⇒x=20

∠B=4x=4×20

=80

The measure of ∠B is 80

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