Question

1) Abhimanyu runs around a rectangular park of length 120m and breadth 75 h Amar runs around a
square park of side 65m. Who covers more distance?​

Answer 1

Answer:

He covers more distance while running around the rectangle.

Step-by-step explanation:

Perimeter of the rectangular park = Distance covered by Abhimanyu = (120x75)m^2

= 9000m^2

Perimeter of a square = 65^2

=4225m^2

Answer 2

Answer:

Distance covered by Abhimanyu = perimeter of the rectangular park

= 2(l + b) units

= [ 2(120+75)] m = [2 (195)] m = 390m

Distance covered by Amar = perimeter of the square park

= 4 × side of square park

(4 × 65) m = 260m

since 390 m > 260m , Abhimanyu covers more distance.

✅ hence Abhimanyu covers more distance.

⛄ hope it helps you