Question

1. Abox has 390 bulbs out of this 26 are defective. A bulb is choosen
at random. Find the probability of the bulb chosen, not being
defective?​

Answer 1

Answer:

364/390 is the correct answer

Answer 2

Answer:

If a box has 390 bulbs out of this 26 are defective. A bulb is chosen at random. then the probability of the bulb chosen, not being defective is 0.933.

Step-by-step explanation:

Given,

Total number of bulbs in a box = 390 and

Number of defective bulbs in a box = 26

∴ Total number of outcomes = 390

Number of non-defective bulbs in a box = 390 - 26 = 364

The favorable outcomes = 364

∴ P(getting a bulb is not defective) = Number of favourable outcomes/total number of possible outcomes

P(getting a bulb is not defective) $= \frac{361}{390}=\frac{182}{195}= 0.933$

Hence, P(getting a bulb is not defective) $= \frac{182}{195} = 0.933.$