Question

1.
Acceleration due to gravity at Earth's surface is 10ms-². The value of acceleration due to gravity at the surface of a planet of mass 1/5th and radius 1/2 of the earth is​

Answer 1

Answer:

F = GMm/r²

F = ma

⇒ GMm/r² = ma

⇒ g = GM/r²

M is divided by 5

R is divided by 2

⇒ g = GM/ 5 × (r/2)² = GM/ 5 × r²/4 = GM × 4/r² × 5 = (GM/r²) × 4/5

So, g is made 4/5 times on the planet

4/5 × 10 = 8 ms⁻²