Question

1 added to the numerator and denominator of a fraction result in 1/2 when 1 is substrated from the denominator result is 1/3 find the fraction​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Fraction = $\frac{3}{7}$

Step-by-step explanation:

Let the fraction be $\frac{x}{y}$

so, ATQ,

1) $\frac{x+1}{y+1}$ = $\frac{1}{2}$

=> $\frac{2(x+1)}{1(y+1)}$ = 1

=> $\frac{2x + 2}{y+1)}$ = 1

=> 2x+2 = y+1

=> y = 2x +1 ———————(1)

2) $\frac{x-1}{y-1}$ = $\frac{1}{3}$

=> $\frac{3(x-1)}{1(y-1)}$ =1

=> $\frac{3x - 3}{y-1)}$ = 1

=> 3x - 3 = y - 1

=> y = 3x - 2 ———————(2)

From (1) and (2)

2x + 1 = 3x - 2

3x - 2x = 1 + 2

x = 3.

y = 2(3) +1

y = 7

Fraction = $\frac{3}{7}$

Verification =

1) $\frac{3+1}{7+1}$ = $\frac{4}{8}$ => $\frac{1}{2}$

2) $\frac{3-1}{7-1}$ = $\frac{2}{6}$ => $\frac{1}{3}$

HENCE PROVED.

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