Question

1 added to the product of two consecutive evev numbers gives 289. What are the numbers?​

Answer 1

${\huge{\underline{\large{\mathbb{\red{KABIR}}}}}}$

first even number =x

next even number = x+2

x(x+2)+1=289

x^2+2x+1=289

(x+1)^2=289

x+1=root289=17

x=17-1=16

numbers =16, 18

Hope this will help u ❤❤

Answer 2

Answer:

Step-by-step explanation: