Question

1
Af 1 + sin² θ = 3 sin theetacos theeta, prove that tan theeta = 1 or
2​

Answer 1

Step-by-step explanation:

$1 + { \ \cos( \alpha ) ) }^{2} = 3 \sin( \alpha ) \cos( \alpha )$

convert all into tan functions we get

1+tan²x/1+tan²x=3tanx/1+tan²x

by solving we get

( tanx-1)(tanx-2)=0

tana=1 or2