Question

1. Aftab tells his daughter, "Seven years ago, I was seven times as old as you were then.
Also, three years from now, I shall be three times as old as you will be." (Isn't this
interesting ?) Represent this situation algebraically and graphically.​

Answer 1

Step-by-step explanation:

Let Aftab's daughter's age be 'x'

7 years ago, (original Age minus 7)

      Aftab's age= 7(x-7) = 7x-49

      Aftab's daughter's age= x-7

3 years after now,(original age plus 3)

        Aftab's age= 3(x-3) = 3x-9

        Aftab's daughter's age= x+3

HOPE YOU FOUND IT USEFUL.

Answer 2

Let A be Aftab

Let D be daughter

Let Aftab's age be x yrs

Let his daughter's age be y yrs

A - 7 = 7(D - 7)

⇒ x - 7 = 7(y - 7)

⇒ x - 7 = 7y - 49

⇒ x - 7y = -42                          …(i)

A + 3 = 7(D + 3)

⇒ x + 3 = 3(y + 3)

⇒ x + 3 = 3y + 9

⇒ x - 3y = 6              ….(ii)

Represented it Algebrically

Solving (i) & (ii)

x   -   7y =   -42

x   -   3y =   6

-----------------------

(-)      (+)     (-)

-4y = -48

y= -48/-4

y = 12

Substituting value of y in (ii)

x-3y=6

x-3(12)=6

x-36=6

x=6+36

x = 42

Plot values of x and y i.e. 42 and 12 on a graph with points (x,y) = (42,12)

Represented it graphically

Hope it helps!!!!!!!!!!