1/alpha-1/beta ....how to solve this?
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α+β=-1
=(α+β)²=(-1)² (squaring both sides)
=(α-β)²+4αβ=1
=(α-β)²+4*(-2)=1
=(α-β)²-8=1
=(α-β)²=9
=α-β=3
=1/α-1/β
=β-α/αβ
=-1(α-β)/αβ
=-1(3)/-2
=-3/-2
=3/2
=(α+β)²=(-1)² (squaring both sides)
=(α-β)²+4αβ=1
=(α-β)²+4*(-2)=1
=(α-β)²-8=1
=(α-β)²=9
=α-β=3
=1/α-1/β
=β-α/αβ
=-1(α-β)/αβ
=-1(3)/-2
=-3/-2
=3/2
tonmoy12:
given polynomial ax^2 +bx+c find(i)1/a×alpha+b + 1/a×beta+b (ii) beta/a×alpha+b + alpha/a×beta+b
can u help with these?
i will mark u just solve bro
done
u done?
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