1 am a factor of 84 and a common multiple of 3 and 7 . The sum of my digit is 3 .the digits are two apart .what number am i?
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Answer:
21
Step-by-step explanation:
1.Its said that the given number is a factor of 84.(21×4=84).
2 .Its also a common multiple of 3 and 7 . The common multiple of 3 and 7 is 3×7=21.
3 .The sum of the given number is 3 and 2+1=3.
4 . The digits are also two apart from each other.
Hence the given number is 21
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