1.Among 240 students, it was found that three - fourth of the students preferred to play hockey and one-eighth of the students preferred to play cricket. The number of students whole prefer to play hockey and cricket respectively are:
2.The distance between two cities X and Y is 50 km. Ramesh travels from city X to city Y by scooter with an average speed of 30 km/h. How long will it take him to reach city Y?
3.Manav took 4 minutes to complete a race comprising three rounds. The time taken to complete the first and the second round is 3/4min and 1 1/2min (one one upon two is written in mixed fraction form)respectively. How much time was taken by Manav to complete the last round?
4.Rakesh had some amla candies. He gave two third of the total candies to Rajan. One fifth to Sumitra and the remaining candies were given to Prasad. If Rakesh had 90 candies, then how many candies were given to Prasad?
5.Don Bradman Scored 7996 runs from 80 innings. Sehwag scored 10000 runs from 160 innings. Rahul Dravid scored 13000 runs from 200 innings. Who scored maximum runs per innings?
Answers
Answered by
7
Answer:
1) students playing hockey=3÷4×240=180
students playing cricket=240÷8=30
2) time = dist.÷ speed=5÷3h
3)candies with rakesh=90
given to rajan=2÷3×90=60
given to sumitra=90÷5=18
thus given to prasad=90-(60+18)=12
5) Bradman's avg.=7996÷80=99.95
sehwag's avg.=10000÷ 160=62.5
David's avg.= 13000÷200=65
thus, highest avg.= don bradman's
Answered by
1
Answer:
1) students playing hockey=3÷4×240=180
students playing cricket=240÷8=30
2) time = dist.÷ speed=5÷3h
3)candies with rakesh=90
given to rajan=2÷3×90=60
given to sumitra=90÷5=18
thus given to prasad=90-(60+18)=12
5) Bradman's avg.=7996÷80=99.95
sehwag's avg.=10000÷ 160=62.5
David's avg.= 13000÷200=65
thus, highest avg.= don bradman's
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