1.Among the following, which one shows the electronic configuration of noble gas ? [ (2,7), (2,8) (2,1), (2,2)]
2.Noble gases do not take part in chemical reactions. Why?
3.The electronic configuration of Sodium (Na) is 2,8,1.
a) Do you think that the atom attains stability?
b) Substantiate your answer.
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Answer:
sorry this big answer
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Explanation:
1. (2,8)
2. The atoms of noble gas already have complete outer shells, so they have no tendency to lose, gain or share electrons. This is why noble gases are inert and do not take part in chemical reactions.
3.(a) Yes, the atoms attain stability by losing, gaining or sharing of electrons.
3.(b) Electionic configuration of Sodium (Na) is 2,8,1
sodium in order to attain stability loses an electron, present in its outermost shell.
so,
No. of protons = 11 = +11
No. of electons = 10 = -10
Overall charge = +11-10 = +1
+1 which is equal to its valency.
Representation
Na – 1e- —> Na+
Thank you
Hope this would help
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