1) Among two supplementary angle, the measure of the larger angle is 36° more than the measure of the smaller. Find their measure?
2) Find the angle which is equal to its supplement?
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Answer:
Since it is given in question that two angles are supplementary, their sum is equal to 180 degrees
Let smaller angle be = x
Larger angle = 36' + x ( as given)
Now 36' + x + x = 180 '
36 + 2x = 180'
2x = 180 -36
2x = 144
x = 144 /2 => 72'
smaller angle is = 72'
Larger angle is 72+36=108'
2) We have to find the angle which is equal to its supplement.
Supplement-
Let the angle be x.
x+x=180∘⇒2x=180∘⇒x=90∘x+x=180∘⇒2x=180∘⇒x=90∘
Hence, the angle which is equal to its supplement is 90 degrees.
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