Question

1&. The lengths of me sites of a triangle are Il em
19. ABC is an isosceles triangle in which AB = BC flerwice the measure of A.
numbers must the length of the third side fall
les triangle measures (18) and one of the base angles me
opposite angles are the
measure of all the angles of the triangle
20. 77e vertical​

Answer 1

Answer:

This implies that

x2+2ax=4x−4a−13

or

x2+2ax−4x+4a+13=0

or

x2+(2a−4)x+(4a+13)=0

Since the equation has just one solution instead of the usual two distinct solutions, then the two solutions must be same i.e. discriminant = 0.

Hence we get that

(2a−4)2=4⋅1⋅(4a+13)

or

4a2−16a+16=16a+52

or

4a2−32a−36=0

or

a2−8a−9=0

or

(a−9)(a+1)=0

So the values of a are −1 and 9.

.............................................................