1. An athlete completes one round of a circular track of diameter
200 m in 40 s. What will be the distance covered and the
displacement at the end of 2 minutes 20 s?
Answers
Answer:
Now, it is given that the time taken to complete one round of the circular track by the athlete = 40s. Thus, the speed of the athlete $=\dfrac{200\pi}{40}=5\pi$ m/s. Therefore, in 2 min 20s or 140s, the distance travelled by the athlete will be $=5\pi \times 140=700\pi$ m.
Explanation:
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Answer:
In 40 s the athelete cover -200m/2 = 100m r
thus the distance cover by the body on 2min, 20s .= 140s
circumference of circle = 2πr
in one round the athelete takes 40 s thus in 140 s thus, rounds taken by the athlete in 140s = 3.5 rounds .
The distance covered by the body is-
circumference of circle = 2πr × no. of rounds .
2×22/7×100×35/10
2200m/s .
Displacement of the body is zero .
the shortest distance of the body , that is diameter 100-100= 0