Question

1. An echo was heard after 3 s.
What is the distance of the
reflecting surface from the
source, given that the speed of
sound is 342 m s-l?​

Answer 1

t = 3s

v = 342m/s

s = vt = (342×3) = 1026m

Required distance = 1026/2 = 513m

Explanation:

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