1. An electric lamp whose resistance 24 Ω and a conductor of 8 Ω resistance are connected in parallel to 28 V battery. Calculate a) total resistance of circuit.
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Answer:
the total resistance of the circuit =20Ω+4Ω=24Ω
b). The current through the circuit= current through the bulb= current through the conductor.
The current through the circuit=
Total Resistance
voltage applied
.
the current through the circuit =
24
6
amp
The current through the circuit = 0.25amp
c). The potential difference across the lamp and the conductor.
(i) The potential difference across the electrical lamp =0.25×20=5volt
(ii) The potential difference conductor =0.25×4=1 volt
d). Power can be calculated as
current through the lamp
voltage across the lamp
power=
0.25
5
→20W
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