Question

1. An electron is moving in a circular path under the
influence of a transverse magnetic field of
3.57 x 10-2 T. If the value of e/m is
1.76 x 1011 C/kg, the frequency of revolution of
the electron is :-
(1) 62.8 MHz
(2) 6.28 MHz
(3) 1 GHz
(4) 100 MHz​

Answer 1

Answer:1GHz

Explanation:

Answer 2

Answer:

T = 2πM/QB

f = 1/T

f = QB /2πM

Q/m = 1.76 × 10^11

B = 3.57 × 10^-2

π = 3.14

f = 10^9 Hz

f = 1G Hz