Question

(1) An elevator descends into a mine shaft at the rate of 5 m/min. If the descent starts from 8m above the ground level, how long will it take to reach 42 m. [means-42 m) below the ground level?​

Answer 1

Answer:

(1) An elevator descends into a mine shaft at the rate of 5 m/min. If the descent starts from 8m above the ground level, how long will it take to reach 42 m. [means-42 m) below the ground level?

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Answer 2

Given:

An elevator descends into a mine shaft at the rate of 5 m/min. If the descent starts from 8m above the ground level, how long will it take to reach 42 m.

Solution:

Find the total distance,

$\[\begin{array}{l} = 8m + 42m\\ = 50m\end{array}\]$

Calculate the time taken to descend 50 m at the rate of 5m/min.

Know that,

Time $\[ = \frac{{{\rm{Distance}}}}{{{\rm{Speed}}}}\]$

Therefore,

$\[\begin{array}{l} = \frac{{50}}{5}\\ = 10\min \end{array}\]$

Hence, the elevator will take 10 min to reach 42 m below the ground from the 8 m above the ground level.