Question

1 An engineering machine has a piston which is going up and down approximately 75 times per minute Describe carefully how a stopwatch may be used to find accurately the time for one up-and- down cycle of the piston.​

Answer 1

Answer:

I don't know

Explanation:

sorry

Answer 2

Given,

The frequency of the engineering machine = 74 oscillations per minute

To find,

The time for one up-and-down cycle of the piston.​

Solution,

The time for one up-and-down cycle or one oscillation is 0.8108 seconds or 0.0135 minutes.

We may easily answer this numerical problem by following the steps below.

We know that,

An engineering machine has a frequency of 74 oscillations per minute, which means 74 oscillations are completed in 60 seconds.

By the unitary method, we know that,

The machine will complete $\frac{74}{60}$ oscillations in 1 second.

Now,

We have to find out the time for 1 oscillation, which will be $\frac{60}{74}$ seconds.

Thus, the time for one up-and-down cycle or one oscillation is 0.8108 seconds or 0.0135 minutes.