Question

1. An iceberg (p = 917 kg/m^3) floats in seawater (p = 1025 kg/m2). (a) What fraction of the iceberg is beneath the
surface of the water? (b) What fraction of the iceberg is above the surface of the water?Correctly answer this...Mark u as a brainliest...​

Answer 1

The weight of the iceberg is Fi = (di)(Vi)g where di is the density of iceberg and Vi is its volume. The upward buoyant force on the iceberg is the weight of the displaced water. This is B=(dw)(Vw)g where dw is the density of water and Vw is the volume of displaced water. Vw is the volume of the iceberg below water. Now Fi=B so (di)(Vi) = (dw)(Vw) and Vw/Vi = di/dw. Now dw=1025 kg/m^3 and di=917 kg/m^3, Vw/Vi = 917/1025 = 0.8946 so nearly 90% of the iceberg is below the water surface.